{"id":6567,"date":"2018-12-25T16:57:29","date_gmt":"2018-12-25T16:57:29","guid":{"rendered":"https:\/\/www.jquery-az.com\/?p=6567"},"modified":"2018-12-25T16:57:29","modified_gmt":"2018-12-25T16:57:29","slug":"python-timedelta","status":"publish","type":"post","link":"https:\/\/www.jquery-az.com\/python-timedelta\/","title":{"rendered":"Python timedelta class"},"content":{"rendered":"

The timedelta is a class in datetime module that represents duration. The delta means average of difference and so the duration expresses the difference between two date<\/a>, datetime<\/a> or time<\/a> instances.<\/p>\n

By using timedelta, you may estimate the time for future and past.<\/p>\n

The syntax of using timedelta <\/strong><\/h3>\n

The timedelta can be defined as:<\/p>\n

class datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0)<\/p><\/blockquote>\n

The default value of all arguments is zero and all are optional<\/strong>.<\/p>\n

The example of using timedelta class<\/strong><\/h3>\n

In this example, we will get the current local date and add seven days by using the timedelta. Have a look:<\/p>\n

#The demo of timedelta class\r\n\r\nimport datetime\r\n\r\n\r\n\r\ndt_now = datetime.datetime.now()\r\n\r\n\r\n\r\nprint('Current Local Date:', dt_now)\r\n\r\nadd_days = dt_now + datetime.timedelta(days=7)\r\n\r\nprint('Adding Seven days: ', add_days)<\/pre>\n
The output as I executed this code:<\/strong><\/p>\n
Current Local Date: 2018-12-10 14:26:08.332603<\/p>\n
Adding Seven days:\u00a0 2018-12-17 14:26:08.332603<\/p><\/blockquote>\n
As timedelta is part of the datetime module, so it is imported upfront. You may also use this command:<\/p>\n
from datetime import datetime, timedelta<\/p><\/blockquote>\n
In that case, rather than using the datetime.datetime.now()<\/em> and datetime.timedelta(days=7),<\/em> you may simply use the datetime.now() and timedelta(days=7)<\/em> to avoid writing extra code.<\/p>\n
Then we got the current time by using the now() function and finally used the timedelta with days argument for adding seven days to the current date.<\/p>\n
Getting yesterday and tomorrow dates example<\/strong><\/h3>\n
In the following example, we will get the current date by today()<\/strong> function. This is followed by getting the date after today and previous date by using the timedelta() as follows:<\/p>\n
#The demo of timedelta class\r\n\r\nfrom datetime import date, timedelta\r\n\r\n\r\n\r\ndt_today = date.today()\r\n\r\nprint ('Current Date\u00a0\u00a0\u00a0 :', dt_today)\r\n\r\n\r\n\r\nTomPrev = timedelta(days=1)\r\n\r\n\r\n\r\n#Applying arithmetics on date\r\n\r\nprint (\"Yesterday Date: \", dt_today - TomPrev)\r\n\r\nprint (\"Tomorrow Date: \", dt_today + TomPrev)<\/pre>\n
The output:<\/strong><\/p>\n
\"Python<\/p>\n
First, you might notice we used the date class from datetime module. The today() function belongs to this date class. This is followed by using the timedelta where days=1 argument is given.<\/p>\n
Get total number of seconds in a day example<\/strong><\/h3>\n
The timedelta() class has a few attributes (min, max, and resolution) and method. The total_seconds<\/strong> method returns the total number of seconds contained in the duration.<\/p>\n
The example below displays the total number of seconds in an hour, day, and a year:<\/p>\n
from datetime import timedelta\r\n\r\n\r\n\r\ny = timedelta(days=365)\r\n\r\ntot_secs_year = y.total_seconds()\r\n\r\n\r\n\r\nd = timedelta(days=1)\r\n\r\ntot_secs_day = d.total_seconds()\r\n\r\n\r\n\r\nh = timedelta(hours=1)\r\n\r\ntot_secs_hour = h.total_seconds()\r\n\r\n\r\n\r\nprint ('Total seconds in an Year\u00a0\u00a0\u00a0 :', tot_secs_year)\r\n\r\nprint ('Total seconds in a Day\u00a0\u00a0\u00a0 :', tot_secs_day)\r\n\r\nprint ('Total seconds in an Hour\u00a0\u00a0\u00a0 :', tot_secs_hour)<\/pre>\n
The result:<\/strong><\/p>\n
\"Python<\/p>\n
Formatting date example with timedelta<\/strong><\/h3>\n
In the following example, we will get the date after one week of the current date, next month date (30 days), and other dates and format the dates by strftime()<\/strong><\/a> function to display in the specified format:<\/p>\n
#timedelta and date formatting\r\n\r\nimport datetime\r\n\r\n\r\n\r\ndate_curr = datetime.datetime.now()\r\n\r\nprint('Today Date:', date_curr.strftime(\"%A, %d %b %Y\"))\r\n\r\n\r\n\r\nadd_month = date_curr + datetime.timedelta(days=30)\r\n\r\nprint('Formatted Date Next Month:', add_month.strftime(\"%A, %d %b %y\"))\r\n\r\n\r\n\r\nadd_week = date_curr + datetime.timedelta(days=7)\r\n\r\nprint('Formatted Date Next Week: ', add_week.strftime(\"%A, %d %b %y\"))\r\n\r\n\r\n\r\nprev_month = date_curr + datetime.timedelta(days=-30)\r\n\r\nprint('Formatted Date Previous Month:', prev_month.strftime(\"%A, %d %b %y\"))\r\n\r\n\r\n\r\nadd_year = date_curr + datetime.timedelta(days=365)\r\n\r\nprint('Formatted Date Next Year:', add_year.strftime(\"%A, %d %b %Y\"))\r\n\r\n\r\n\r\nprev_year = date_curr + datetime.timedelta(days=-365)\r\n\r\nprint('Formatted Date Previous Year:', prev_year.strftime(\"%A, %d %b %Y\"))<\/pre>\n
The output as I executed this code:<\/strong><\/p>\n
Today Date: Tuesday, 11 Dec 2018<\/p>\n
Formatted Date Next Month: Thursday, 10 Jan 19<\/p>\n
Formatted Date Next Week:\u00a0 Tuesday, 18 Dec 18<\/p>\n
Formatted Date Previous Month: Sunday, 11 Nov 18<\/p>\n
Formatted Date Next Year: Wednesday, 11 Dec 2019<\/p>\n
Formatted Date Previous Year: Monday, 11 Dec 2017<\/p><\/blockquote>\n
 <\/p>\n","protected":false},"excerpt":{"rendered":"
The timedelta is the class in datetime module that represents duration. The delta means average of difference and so the duration expresses the difference between two date, datetime or time instances.<\/p>\n","protected":false},"author":1,"featured_media":6568,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":[],"categories":[17],"tags":[],"yoast_head":"\nWhat is Python timedelta? Explained with 4 Examples<\/title>\n<meta name=\"description\" content=\"The timedelta is the class in datetime module that represents duration. 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